A screw gauge gives the following readings when used to measure the diameter of a wire
Main scale reading : 0 mm
Circular scale reading : 52 divisions
Given that 1 mm on main scale corresponds to 100 divisions on the circular scale. The diameter of the wire from the above data is

(1). 0.52 cm
(2). 0.026 cm
(3). 0.26 cm
(4). 0.052 cm

Number of Attempts: 2

Correct Attempts: 1

Time Taken: 00:04

Average Time: 00:02

Consider the diameter of a spherical object being measured with the help of a Vernier callipers. Suppose its 10 Vernier Scale Divisions (V S D) are equal to its 9 Main Scale Divisions (M S D). The least division in the M S is 0.1 cm and the zero of V S is at x = 0.1 cm when the jaws of Vernier callipers are closed. If the main scale reading of the diameter is M = 5 cm and the number of coinciding vernier division is 8, the measured diameter after zero error correction is

(1). 5.00 cm
(2). 5.18 cm
(3). 5.08 cm
(4). 4.98 cm

Number of Attempts: 2

Correct Attempts: 1

Time Taken: 00:04

Average Time: 00:02

In a vernier callipers, (N + 1) divisions of vernier scale coincide with N divisions of main scale. If 1 MSD represents 0.1mm, the vernier constant (in cm) is:

(1). 1/10N
(2). 1/100(N + 1)
(3). 100N
(4). 10(N + 1)

Number of Attempts: 2

Correct Attempts: 1

Time Taken: 00:04

Average Time: 00:02

A screw gauge has least count of 0.01 mm and there are 50 divisions in its circular scale. The pitch of the screw gauge is :

(1). 0.25 mm
(2). 0.5 mm
(3). 1.0 mm
(4). 0.01 mm

Number of Attempts: 2

Correct Attempts: 1

Time Taken: 00:04

Average Time: 00:02

A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm, the correct diameter of the ball is

(1). 0.521 cm
(2). 0.525 cm
(3). 0.053 cm
(4). 0.529 cm

Number of Attempts: 2

Correct Attempts: 1

Time Taken: 00:04

Average Time: 00:02